StackOverflow Rank and Percentile

104

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Reverse Engineering

Q&A for researchers and developers who explore the principles of a system through analysis of its structure, function, and operation

-- StackOverflow Rank and Percentile

WITH Rankings AS (
SELECT Id, Ranking = ROW_NUMBER() OVER(ORDER BY Reputation DESC)
FROM Users
)
,Counts AS (
SELECT Count = COUNT(*)
FROM Users
WHERE Reputation > 100
)
SELECT Id, Ranking, CAST(Ranking AS decimal(20, 5)) / (SELECT Count FROM Counts) AS Percentile
FROM Rankings
WHERE Id = ##UserId##

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