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Русский язык Meta

Q&A for лингвистов, этимологов, и энтузиастов русского языка

    Answers AS (
        SELECT *
            FROM Posts
            WHERE PostTypeId = 2 -- Answers

Select top 50 AS [question_id], AS [answer_id],
questions.acceptedanswerid AS [accepted_id],
answers.score AS [answer_score]
FROM posts AS questions
JOIN answers ON = answers.parentid

WHERE questions.AnswerCount >=3 and questions.OwnerUserId not in
(SELECT OwnerUserId From answers 
WHERE answers.ParentId = questions.Id)

ORDER BY questions.creationdate

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