See http://meta.stackoverflow.com/q/86165/13992 ~ Please mind, this query does not account for bounties or suspensions.
Q&A for programmers
-- Enter Query Title -- Enter Query Description select owneruserid as [User Link], Reputation, 10*(1 + reputation/100) as "Questions allowed", count(*) as "Questions asked", count(*) - 10*(1 + reputation/100) as "Excess questions" from posts join users on posts.owneruserid = users.id where posttypeid = 1 group by OwnerUserId, reputation having count(*) > 10*(1 + reputation/100) order by count(*) - 10*(1 + reputation/100) desc
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