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Q&A for power users of Apple hardware and software

SELECT
  t.Tagname,
  COUNT(a.Id) AS [Count],
  SUM(a.Score) AS [Score]
FROM Posts a INNER JOIN Posts q ON a.ParentId=q.Id
  INNER JOIN PostTags pt ON pt.PostId=q.Id
  INNER JOIN Tags t ON t.Id=pt.TagId
WHERE  (a.OwnerUserId=##userid?39599##)
GROUP BY t.TagName
ORDER BY Count(a.Id) DESC

fork query

edited jul 15

created jul 15 Martin20528