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SELECT top 10 * from Tags where TagName = 'javascript'

SELECT
    Top 100
    ROW_NUMBER() OVER(ORDER BY Reputation DESC) AS [#], 
    Id AS [User Link], 
    Reputation
FROM
    Users
WHERE
     LOWER(Location) LIKE LOWER('%zealand%')
     AND (SELECT count(Id) from Tags where TagName = 'javascript') > 1
     
ORDER BY
    Reputation DESC;

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