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Q&A for users and developers of the Cardano cryptocurrency ecosystem

SELECT u.Id AS [User Link],
  MAX(b.Name) AS 'One of the gold badges they have',
  COUNT(*) AS 'Number of gold badges'
FROM Users AS u
INNER JOIN Badges AS b
  ON b.UserId = u.Id
WHERE b.Class = 1
GROUP BY u.Id
ORDER BY COUNT(*) DESC;

fork query

created nov 4 23 galacticninja