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Q&A for users and developers of the Cardano cryptocurrency ecosystem

SELECT TOP(##num?100##)
  RANK() OVER(ORDER BY COUNT(*) DESC) AS Rank,
  b.UserId AS [User Link],
  COUNT(*) AS [Count],
  MAX(b.Date) As [The Most Recent]
FROM Badges b INNER JOIN Users u ON b.UserId=u.Id
  WHERE (b.Name = '##name?Great Answer##')
GROUP BY b.UserId
ORDER BY COUNT(*) DESC, MAX(b.Date) DESC

fork query

edited feb 8

created feb 8 Martin20528