SELECT Tags.TagName, COUNT(*) as IssueCount, AVG(CAST(Pos...

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Chinese Language

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-- Query 13: Technology Integration Challenges
-- Identifies AI/ML opportunities (Question 3)
SELECT 
    Tags.TagName,
    COUNT(*) as IssueCount,
    AVG(CAST(Posts.Score as FLOAT)) as AvgScore,
    SUM(Posts.ViewCount) as TotalViews
FROM Posts
LEFT JOIN PostTags ON Posts.Id = PostTags.PostId
LEFT JOIN Tags ON PostTags.TagId = Tags.Id
WHERE Tags.TagName IN ('mobile-apps', 'online-booking', 'websites', 'technology')
    AND Posts.PostTypeId = 1
GROUP BY Tags.TagName
ORDER BY IssueCount DESC;

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