SELECT ROUND((SELECT count(*) FROM Users WHERE Reputation...

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Programming Puzzles and Code Golf

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SELECT ROUND((SELECT count(*) FROM Users WHERE Reputation >= 20000) / 3.0, 2),
       ROUND((SELECT count(*) FROM Users WHERE Reputation >= 10000) / 10.0, 2),
       ROUND((SELECT count(*) FROM Users WHERE Reputation >= 3000) / 80.0, 2),
       ROUND((SELECT count(*) FROM Users WHERE Reputation >= 2000) / 120.0, 2)

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