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Q&A for software developers, mathematicians and others interested in cryptography

select DisplayName
from Users
where Id = (
    select distinct OwnerUserId
    from Posts
    where year(CreationDate) = 2010
)
and Id = (
    select distinct OwnerUserId
    from Posts
    where YEAR(CreationDate) = 2015
);

view current version

edited dec 13

created dec 12 jon.doe46562