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Q&A for Drupal developers and administrators

SELECT TOP(##num?100##)
RANK() OVER(ORDER BY SUM(a.Score) DESC) AS Rank,
q.Id AS [Post Link],
SUM(a.Score) AS [Total Score],
COUNT(a.Id) AS [# of answers]
FROM Posts q INNER JOIN Posts a ON a.ParentId=q.Id
GROUP BY q.Id
ORDER BY SUM(a.Score) DESC

fork query

edited nov 8

created nov 8 Martin20528