Q&A for electronics and electrical engineering professionals, students, and enthusiasts
SELECT Reputation, 100.0 * SUM(COUNT(*)) OVER (ORDER BY Reputation) / SUM(COUNT(*)) OVER() AS CumPct FROM Users GROUP BY Reputation HAVING Reputation = 726 ORDER BY Reputation -- Forked from: smithmartin -- https://meta.stackoverflow.com/questions/349805/where-do-i-stand-in-the-reputation-distribution -- https://data.stackexchange.com/stackoverflow/query/676644/rep-distribution#resultSets