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Q&A for electronics and electrical engineering professionals, students, and enthusiasts

SELECT Reputation,
       COUNT(*) AS RepCount,
       SUM(COUNT(*)) OVER (ORDER BY Reputation DESC) AS RepCumulativeCount,
       COUNT(*) OVER() AS TotalUserCount
FROM Users
GROUP BY Reputation
ORDER BY Reputation

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edited may 27 17

created may 27 17 smithmartin