SELECT top(5) b.Name, COUNT(b.id) as skaits FROM Users as u

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Esperanto Language

Q&A for teachers and students of the Esperanto language

SELECT top(5)
  b.Name, 
  COUNT(b.id) as skaits
FROM Users as u
INNER JOIN Badges as b ON b.userid = u.id
where u.DisplayName like 'Andr%'
group by b.Name 
order by skaits desc

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