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SELECT tgs.TagName as Tag ,COUNT(1) as NoOfTags FROM Tags...

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Esperanto Language

Q&A for teachers and students of the Esperanto language

SELECT tgs.TagName as Tag
	,COUNT(1) as NoOfTags
FROM Tags tgs 
WHERE 1=1
	and UPPER(tgs.TagName) = 'CSS'
GROUP BY tgs.TagName
;
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