Question 5

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Esperanto Language Meta

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WITH PostWithTagCounts AS (
    SELECT Top 10
        Posts.Id AS PostId,
        Posts.OwnerUserId AS UserId,
        Posts.Body AS PostBody,
        COUNT(PostTags.TagId) AS NumberOfTags,
        STRING_AGG(Tags.TagName, ', ') AS Tags
    FROM 
        Posts
    JOIN PostTags ON Posts.Id = PostTags.PostId
    JOIN Tags ON PostTags.TagId = Tags.Id
    WHERE 
        Posts.Tags IS NOT NULL
    GROUP BY 
        Posts.Id, Posts.OwnerUserId, Posts.Body
)
SELECT *
FROM PostWithTagCounts
WHERE NumberOfTags >= 5
ORDER BY NumberOfTags DESC;

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