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Q&A for gardeners and landscapers

CREATE TABLE #tbl(
	rater_id	VARCHAR(3),
	facility_code	VARCHAR(15),
	rate_one		INT,
    rate_two        INT
);
INSERT INTO #tbl VALUES
('1',	'123',	NULL,	NULL),
('2',	'123',	NULL,	NULL),
('3',	'123',	1,	NULL),
('4',	'123',	1,	NULL),
('5',	'888',	0,	NULL),
('6',	'888',	1,	NULL),
('7',	'888',	1,	NULL),
('8',	'888',	2,	NULL),
('9',	'69420',	3,	NULL);

SELECT COUNT(rater_id)

FROM #tbl
WHERE facility_code = '123'
GROUP BY rater_id;

DROP TABLE #tbl;

fork query

edited aug 24

created mar 10 16 anonymous