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Q&A for gardeners and landscapers

SELECT t.TagName, COUNT(DISTINCT(p.Id))
  FROM Tags AS t
  INNER JOIN PostTags AS pt ON t.Id = pt.TagId
  INNER JOIN Posts AS p ON p.Id = pt.PostId
  WHERE p.AnswerCount = 0 AND year(p.CreationDate) = ##Year## 
  GROUP BY t.TagName
  ORDER BY COUNT(DISTINCT(p.Id)) DESC

fork query

edited jan 27 Rubén

created may 18 19 Glorfindel