Mean Expertise Contribution (MEC) in a tag


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Amateur Radio

Q&A for amateur radio enthusiasts


with answers as (
  select a.OwnerUserId UserId,
         rank() over (partition by q.Id order by a.Score desc) AU,
         1 answers
  from Posts q
       join Posts a on q.Id = a.ParentId
       join PostTags on q.Id = PostId
       join Tags t on TagId = t.Id
  where TagName = '##tag##' --and q.Id = 9929585

select UserId as [User Link],
       sum(AU), count(answers)
from answers
group by UserId
order by avg(AU) desc

Enter Parameters

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