StackOverflow Rank and Percentile

122

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Health Meta

Q&A about the site for professionals in medical and allied health fields, students of those professions, related academics, and others with a sound understanding of medicine and healthcare-related sciences

-- StackOverflow Rank and Percentile

WITH Rankings AS (
SELECT Id, Ranking = ROW_NUMBER() OVER(ORDER BY Reputation DESC)
FROM Users
)
,Counts AS (
SELECT Count = COUNT(*)
FROM Users
WHERE Reputation > 100
)
SELECT Id, Ranking, CAST(Ranking AS decimal(20, 5)) / (SELECT Count FROM Counts) AS Percentile
FROM Rankings
WHERE Id = ##UserId##

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