SELECT TOP 100 a.OwnerDisplayName, (CAST(Count(a.Id) AS f...

0

Please login or register to vote for this query.

(click on this box to dismiss)

Interpersonal Skills

Q&A for people looking to improve their interpersonal communication skills

SELECT TOP 100
    a.OwnerDisplayName,
    (CAST(Count(a.Id) AS float) /
(SELECT Count(*) FROM Posts WHERE PostTypeId = 2) * 100) AS AcceptedPercentage
FROM
    Posts q
  INNER JOIN
    Posts a ON q.AcceptedAnswerId = a.Id

WHERE a.PostTypeId = 2

GROUP BY a.OwnerDisplayName

ORDER BY AcceptedPercentage DESC

Enter Parameters

Options:
Switch to meta site
loading Hold tight while we fetch your results