SELECT a.OwnerDisplayName, (CAST(Count(a.Id) AS float) / ...

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Interpersonal Skills

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SELECT
    a.OwnerDisplayName,
    (CAST(Count(a.Id) AS float) /
(SELECT Count(*) FROM Posts WHERE PostTypeId = 2) * 100) AS AcceptedPercentage
FROM
    Posts q
  INNER JOIN
    Posts a ON q.AcceptedAnswerId = a.Id

WHERE a.PostTypeId = 2
  AND a.OwnerDisplayName = 'DMA57361'

GROUP BY a.OwnerDisplayName

ORDER BY AcceptedPercentage DESC

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