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Iota

Q&A for users of Iota, the open-source cryptocurrency for IoT that does not use a blockchain

DECLARE @UserId int = ##UserId##
-- Enter Query Title
-- Enter Query Description

select  a.* 
--count(case when a. VoteTypeId = 2 then 1 end),
--count(case when a. VoteTypeId = 3 then 1 end)
from PostFeedback a
inner join Posts b on a.PostId = b.Id
inner join PostTypes c on b.PostTypeId = c.Id
where b.OwnerUserId = @UserId;

Enter Parameters

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