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Iota

Q&A for users of Iota, the open-source cryptocurrency for IoT that does not use a blockchain

DECLARE @UserId int = ##UserId##
-- Enter Query Title
-- Enter Query Description
select * from VoteTypes;

select * from PostTypes;

--select distinct b.PostTypeId
--from Votes a inner join Posts b
--on a.PostId = b.Id;

Enter Parameters

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