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Iota

Q&A for users of Iota, the open-source cryptocurrency for IoT that does not use a blockchain

DECLARE @UserId int = ##UserId##
-- Enter Query Title
-- Enter Query Description
--select * from VoteTypes;

--select * from PostTypes;

select top 20 Id, sum(Score)
from
(
select UserId as Id, Score
from Comments 
where Userid is not null
--where Userid = @UserId
union all
select OwnerUserId as Id, Score 
from Posts 
where OwnerUserId is not null
--where OwnerUserId = @UserId
) as w
group by Id;

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