Q&A for users of Iota, the open-source cryptocurrency for IoT that does not use a blockchain
DECLARE @UserId int = ##UserId## -- Enter Query Title -- Enter Query Description --select * from VoteTypes; --select * from PostTypes; select a.Id as [Post Link], a.*,b.* from Posts a inner join Votes b on a.Id = b.PostId where a.OwnerUserId = @UserId order by 2;