Q&A for users of Iota, the open-source cryptocurrency for IoT that does not use a blockchain
DECLARE @UserId int = ##UserId## -- Enter Query Title -- Enter Query Description --select * from VoteTypes; --select * from PostTypes; select round(cast(ViewCount as float)/DATEDIFF(dd,CreationDate,getdate()),1), Id as [Post Link] from Posts where PostTypeId = 2 and OwnerUserId = @UserId;