Q&A for users of Iota, the open-source cryptocurrency for IoT that does not use a blockchain
DECLARE @UserId int = ##UserId## -- Enter Query Title -- Enter Query Description --select * from VoteTypes; --select * from PostTypes; select * from Posts a where PostTypeId = 2 and OwnerUserId = @UserId and exists (select 1 from Posts b where a.Id = b.AcceptedAnswerId);