select Year(CreationDate) as [Year], count(*) as [Users] ...

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Iota

Q&A for users of Iota, the open-source cryptocurrency for IoT that does not use a blockchain

select Year(CreationDate) as [Year], count(*) as [Users] from Users 
where Year(CreationDate)>=2010 group by Year(CreationDate) order by Year(CreationDate)

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