(the extreme self-learners)
Q&A for users of Iota, the open-source cryptocurrency for IoT that does not use a blockchain
SELECT TOP 100 Users.Id AS [User Link], (CAST(Count(a.Id) AS float) / CAST((SELECT Count(*) FROM Posts p WHERE p.OwnerUserId = Users.Id AND PostTypeId = 1) AS float) * 100) AS SelfAnswerPercentage FROM Posts q INNER JOIN Posts a ON q.AcceptedAnswerId = a.Id INNER JOIN Users ON Users.Id = q.OwnerUserId WHERE q.OwnerUserId = a.OwnerUserId GROUP BY Users.Id, DisplayName HAVING Count(a.Id) > 10 ORDER BY SelfAnswerPercentage DESC