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Q&A about the site for users of Iota, the open-source cryptocurrency for IoT that does not use a blockchain

SELECT 
    P.Id AS QuestionId,
    AVG(A.Score) AS AvgAnswerScore
FROM Posts P
JOIN Posts A ON P.Id = A.ParentId
WHERE P.PostTypeId = 1 AND P.AnswerCount > 5
GROUP BY P.Id;

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edited dec 6

created dec 6 jon.doe46505