Q&A about the site for users of Iota, the open-source cryptocurrency for IoT that does not use a blockchain
SELECT TOP 10 TagName, COUNT(*) AS TagCount FROM Tags JOIN PostTags ON Tags.Id = PostTags.TagId JOIN Posts ON Posts.Id = PostTags.PostId WHERE Tags.TagName IN ('vacation-rentals', 'property-management') GROUP BY TagName ORDER BY TagCount DESC;