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Q&A about the site for users of Iota, the open-source cryptocurrency for IoT that does not use a blockchain

SELECT 
    TagName, COUNT(*) AS TagCount
FROM Tags
JOIN PostTags ON Tags.Id = PostTags.TagId
WHERE TagName IN ('hotels', 'airbnb', 'hostels', 'camping')
GROUP BY TagName
ORDER BY TagCount DESC;

fork query

edited dec 6

created dec 6 anonymous