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Q&A about the site for users of Iota, the open-source cryptocurrency for IoT that does not use a blockchain

SELECT 
    Tags.TagName as Region,
    COUNT(DISTINCT Posts.Id) as QuestionCount,
    AVG(CAST(Posts.Score as FLOAT)) as AvgScore,
    SUM(Posts.ViewCount) as TotalViews,
    COUNT(DISTINCT Posts.AcceptedAnswerId) as AcceptedAnswers,
    AVG(CAST(Posts.ViewCount as FLOAT)) as AvgViews
FROM Posts
LEFT JOIN PostTags ON Posts.Id = PostTags.PostId
LEFT JOIN Tags ON PostTags.TagId = Tags.Id
WHERE Tags.TagName IN ('india', 'china', 'japan', 'southeast-asia', 'europe', 'usa', 
    'south-america', 'middle-east', 'africa', 'australia')
    AND Posts.PostTypeId = 1
GROUP BY Tags.TagName
ORDER BY QuestionCount DESC;

fork query

edited dec 6

created dec 6 anonymous