Q&A about the site for users of Iota, the open-source cryptocurrency for IoT that does not use a blockchain
SELECT Users.location as Location, Tags.TagName as TransportType, COUNT(DISTINCT Posts.Id) as QuestionCount, AVG(CAST(Posts.Score as FLOAT)) as AvgScore, SUM(Posts.ViewCount) as TotalViews FROM Posts LEFT JOIN PostTags ON Posts.Id = PostTags.PostId LEFT JOIN Tags ON PostTags.TagId = Tags.Id LEFT JOIN Users ON Posts.OwnerUserId = Users.Id WHERE Tags.TagName IN ('air-travel', 'trains', 'car-rentals', 'public-transport', 'cruise') AND Posts.PostTypeId = 1 GROUP BY Users.Location, Tags.TagName ORDER BY QuestionCount DESC;