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Q&A about the site for users of Iota, the open-source cryptocurrency for IoT that does not use a blockchain

SELECT 
    P.OwnerUserId AS UserId,
    AVG(P.Score) AS AvgAnswerQuality
FROM Posts P
WHERE P.PostTypeId = 2
GROUP BY P.OwnerUserId
HAVING COUNT(*) > 0
ORDER BY AvgAnswerQuality DESC;

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edited dec 7

created dec 7 jon.doe46505