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SELECT OwnerUserId AS UserId, COUNT(*) AS TotalAnswers FR...

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Iota Meta

Q&A about the site for users of Iota, the open-source cryptocurrency for IoT that does not use a blockchain

SELECT 
    OwnerUserId AS UserId,
    COUNT(*) AS TotalAnswers
FROM Posts
WHERE PostTypeId = 2
GROUP BY OwnerUserId
HAVING COUNT(*) > 1000;
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