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プログラマーとプログラミングに熱心な人々のための質問と回答

-- Top users  Algeria

SELECT
    RANK() OVER(ORDER BY Reputation DESC) AS [#], 
    Id AS [User Link], 
    Reputation
FROM
    Users
WHERE
    LOWER(Location) LIKE '%alger%'
    or
    LOWER(Location) LIKE '%algér%'
ORDER BY
    Reputation DESC;

fork query

edited jan 22 anonymous

created jul 3 18 YCF_L