STackoverflow #8844796

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プログラマーと熱狂的なプログラマーのためのサイトに関する質問と回答

with t as (
  select '28 Smith Avenue^MOOROOLBARK VIC 3138^' as str
  union
  select '16 Farr Street^HEYFIELD VIC 3858^' as str
  union
  select '17 Terry Road^LOWER PLENTY VIC 3093^' as str
), t1 as (
  select
    str,
    left(str, charindex('^', str) - 1) as street_address,
    reverse(substring(reverse(str), 2, 4)) as postal_code,
    reverse(substring(reverse(str), 6, len(str) - charindex('^', str) - 6)) as second_part
  from t
)
select 
  street_address,
  postal_code,
  second_part,
  charindex(' ', reverse(second_part))
from t1

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