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Q&A for linguists, teachers and students of the Korean language

-- Relación entre reputación del usuario y la calidad de sus respuestas
DECLARE @TagName NVARCHAR(100) = 'java'

SELECT 
    u.Reputation AS ReputacionUsuario,
    COUNT(a.Id) AS TotalRespuestas,
    COUNT(CASE WHEN a.Score >= 5 THEN 1 END) AS RespuestasConAltosVotos,
    COUNT(CASE WHEN p.AcceptedAnswerId = a.Id THEN 1 END) AS RespuestasAceptadas,
    ROUND((COUNT(CASE WHEN a.Score >= 5 THEN 1 END) * 100.0) / COUNT(a.Id), 2) AS PorcentajeAltosVotos,
    ROUND((COUNT(CASE WHEN p.AcceptedAnswerId = a.Id THEN 1 END) * 100.0) / COUNT(a.Id), 2) AS PorcentajeRespuestasAceptadas
FROM 
    Posts p
JOIN 
    PostTags pt ON p.Id = pt.PostId
JOIN 
    Tags t ON t.Id = pt.TagId
JOIN 
    Posts a ON a.ParentId = p.Id AND a.PostTypeId = 2 -- Respuestas
JOIN 
    Users u ON a.OwnerUserId = u.Id
WHERE 
    t.TagName = @TagName
    AND p.PostTypeId = 1 -- Preguntas
GROUP BY 
    u.Reputation
ORDER BY 
    u.Reputation DESC

fork query

edited sep 7

created sep 6 anonymous