Rep distribution

Please login or register to vote for this query.

(click on this box to dismiss)

Q&A for linguists, teachers and students of the Korean language

SELECT Reputation,
SUM(COUNT(*)) OVER() - SUM(COUNT(*)) OVER (ORDER BY Reputation) AS Rep
FROM Users
GROUP BY Reputation
ORDER BY Reputation

edited aug 11

anonymous

created may 27 17

smithmartin

Options: Text-only results Include execution plan

Switch to meta site

Hold tight while we fetch your results

Results[:current/:total] Messages Graph Execution Plan

Download CSV Download XML

:records returned in :time ms:cached