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Q&A for students, teachers, polyglots, and anyone interested in the techniques of second-language acquisition

/* How much each user asked questions and gave answers

Random sample of users is taken (for research).

PostTypeId = 1 is question
PostTypeId = 2 is answer
*/


;WITH UsersSample AS
(
  SELECT u.Id
  FROM Users u tablesample(1 percent)
  )
  SELECT p.PostTypeId, p.OwnerUserId, p.OwnerUserId AS [User Link],
  COUNT(*) as n
FROM Posts p
RIGHT OUTER JOIN UsersSample u ON u.Id = p.OwnerUserId
WHERE p.OwnerUserId > 0
GROUP BY p.OwnerUserId, p.PostTypeId
ORDER BY p.OwnerUserId, p.PostTypeId

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edited jan 2 14

created dec 21 13 Anton.