Distribution of Users on Questions Count

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Latin Language

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SELECT QCNT as QuestionsCount, count(*) as UsersCount
FROM (

  SELECT 
    OwnerUserId,
    Count(*) as QCNT
  FROM Posts d 
  WHERE
    d.PostTypeId = 1  -- 1=Question
  Group By OwnerUserId
  
  ) as t1
group by QCNT
order by QCNT

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