user persona


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Latin Language

Q&A for linguists, teachers, and students wanting to discuss the finer points of the Latin language

select Tags.TagName, count(Tags.TagName) c
from Users
join Posts on Users.ID = Posts.OwnerUserId
join PostTags on PostTags.PostId =Posts.Id
join Tags on Tags.Id = PostTags.TagId
where datalength(AboutMe) > 0 
  and LastAccessDate  > DATEADD(year, -1, GetDate())
  and datalength(Posts.Tags) > 0
  and upper(AboutMe) like '%PROFESSIONAL%'
group by Tags.TagName
order by c DESC

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