Q&A for people looking to bypass life's everyday problems with simple tricks
create table #ACTOR (name varchar(max), age int, salary int) create table #MOVIE (title varchar(max), studioname varchar(max), directorname varchar(max), budget int, movieyear int) create table #APPEARS (actorname varchar(max), movietitle varchar(max)) insert into #ACTOR values ('Tom', 45, 10000000), ('Denzel', 45, 11000000), ('Ryan', 27, 8000000), ('Seth', 31, 4000000), ('Brad', 45, 15000000), ('George', 45, 15000000), ('Meryl Streep', 55, 12000000), ('Jim', 45, 9000000), ('Chris', 25, 5000000), ('Keanu', 40, 5000000) insert into #MOVIE values ('MovieA', 'StudioA', 'DirectorA', 100000000, 2000), ('Movie1', 'Studio1', 'Director1', 100000000, 2000), ('MovieB', 'StudioA', 'DirectorA', 10000000, 2002), ('MovieC', 'StudioA', 'DirectorA', 100000000, 2003), ('MovieD', 'StudioB', 'DirectorB', 100000000, 2004), ('MovieE', 'StudioB', 'DirectorB', 100000000, 2006), ('MovieF', 'StudioB', 'DirectorA', 100000000, 2007), ('MovieG', 'StudioC', 'DirectorC', 100000000, 2008), ('MovieH', 'StudioC', 'DirectorB', 100000000, 2010), ('MovieI', 'StudioD', 'DirectorD', 100000000, 2011), ('MovieJ', 'StudioD', 'DirectorA', 100000000, 2012), ('MovieK', 'StudioE', 'DirectorC', 100000000, 2012), ('MovieL', 'StudioC', 'DirectorC', 10000000, 2009), ('MovieM', 'StudioD', 'DirectorA', 101000000, 2009), ('MovieN', 'StudioE', 'DirectorB', 101000000, 2009), ('MovieO', 'StudioE', 'DirectorD', 90000000, 2009), ('MovieP', 'StudioF', 'John Huston', 90000000, 2009), ('MovieQ', 'StudioF', 'John Huston', 90000000, 2010), ('Movie', 'Studio', 'Steven Spielberg', 10000000, 1990), ('Movie', 'Studio', 'Steven Spielberg', 10000000, 1991), ('Movie', 'Studio', 'Steven Spielberg', 10000000, 1992), ('Movie', 'Studio', 'Steven Spielberg', 10000000, 1993), ('Movie', 'Studio', 'Steven Spielberg', 10000000, 1994), ('Movie', 'Studio', 'Steven Spielberg', 10000000, 1995), ('Movie', 'Studio', 'Steven Spielberg', 10000000, 1996), ('Movie', 'Studio', 'Steven Spielberg', 10000000, 1997), ('Movie', 'Studio', 'Steven Spielberg', 10000000, 1998), ('Movie', 'Studio', 'Steven Spielberg', 10000000, 1999), ('Movie', 'Studio', 'Steven Spielberg', 10000000, 2000), ('Movie', 'Studio', 'Steven Spielberg', 10000000, 2001), ('Movie', 'Studio', 'Steven Spielberg', 10000000, 2002), ('Movie', 'Studio', 'Steven Spielberg', 10000000, 2003), ('Movie', 'Studio', 'Steven Spielberg', 10000000, 2004), ('Movie', 'Studio', 'Steven Spielberg', 10000000, 2005), ('Movie', 'Studio', 'Steven Spielberg', 10000000, 2006), ('Movie', 'Studio', 'Steven Spielberg', 10000000, 2007), ('Movie', 'Studio', 'Steven Spielberg', 10000000, 2008), ('Movie', 'Studio', 'Steven Spielberg', 10000000, 2009), ('Movie', 'Studio', 'Steven Spielberg', 10000000, 2010), ('Movie', 'Studio', 'Steven Spielberg', 10000000, 2010) insert into #APPEARS values ('Tom', 'MovieA'), ('Ryan', 'MovieA'), ('Chris', 'Movie1'), ('Keanu', 'Movie1'), ('Tom', 'MovieB'), ('Tom', 'MovieC'), ('Denzel', 'MovieB'), ('Denzel', 'MovieC'), ('Denzel', 'MovieD'), ('Ryan', 'MovieD'), ('Meryl Streep', 'MovieE'), ('Meryl Streep', 'MovieB'), ('Meryl Streep', 'MovieC'), ('Jim', 'MovieJ'), ('Jim', 'MovieK'), ('Brad', 'MovieG'), ('Brad', 'MovieL'), ('Brad', 'MovieM'), ('George', 'MovieP'), ('Brad','MovieP'), ('George', 'MovieQ'), ('Chris', 'MovieE'), ('Chris', 'MovieC') select a.name from #actor a where a.name <> 'Meryl Streep' AND ( select count(*) from ( (select movietitle from #appears where actorname = a.name) intersect (select movietitle from #appears where actorname = 'Meryl Streep') ) temp ) >= 2 drop table #actor drop table #movie drop table #appears