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Q&A for people looking to bypass life's everyday problems with simple tricks

select ParentId as "Post Link", OwnerUserId as "User Link", count(*) as "Number of Answers"
from Posts
where ParentId > 0
and OwnerUserId > 0
group by ParentId, OwnerUserId
having count(*) >= 2
order by OwnerUserId desc

fork query

edited dec 1 12 anonymous

created oct 15 12 Adam Lear