Q&A for professional mathematicians
SELECT TOP(##num?100##) RANK() OVER (ORDER BY COUNT(ph.Id) DESC) AS [Rank], COUNT(ph.Id) AS [Count], ph.PostId AS [Post Link], 'site://posts/' + CAST(ph.PostId AS varchar)+'/revisions' AS [Revision History] FROM PostHistory ph WHERE ph.PostHistoryTypeId=50 ---50 = Bumped by Community User GROUP BY ph.PostId ORDER BY COUNT(ph.Id) DESC