StackOverflow Rank and Percentile by location

0

Please login or register to vote for this query.

(click on this box to dismiss)

Ask Ubuntu Meta

Q&A about the site for Ubuntu users and developers

-- StackOverflow Rank and Percentile

WITH Rankings AS (
SELECT Id, Location, Ranking = ROW_NUMBER() OVER(ORDER BY Reputation DESC)
FROM Users
)
,Counts AS (
SELECT Count = COUNT(*)
FROM Users
WHERE Reputation > 100
)
SELECT Id, Location, Ranking, CAST(Ranking AS decimal(10, 5)) / (SELECT Count FROM Counts) AS Percentile
FROM Rankings
WHERE 
Id = ##UserId## 
AND 
Location LIKE '%##Location##%'

Enter Parameters

Options:
Switch sites:
loading Hold tight while we fetch your results