8

Please login or register to vote for this query.

(click on this box to dismiss)

Q&A about the site for expert genealogists and people interested in genealogy or family history

select COUNT(*), q.OwnerUserId as [User Link], a.OwnerUserId as [User Link]
from Posts q
inner join Posts a on q.AcceptedAnswerId=a.Id
inner join Users qu on qu.Id = q.OwnerUserId
inner join Users qa on qa.Id = a.OwnerUserid
where qu.Id != qa.Id
group by q.OwnerUserId, a.OwnerUserId
order by COUNT(*) desc

view current version

edited aug 9 14

created aug 9 14 Undo