Rep distribution


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Q&A about the site for speakers of German wanting to discuss the finer points of the language and translation

SELECT 100-cumpct as 'Top %', MIN(reputation) as 'Reputation' from (SELECT Reputation,
floor(100.0 * SUM(COUNT(*)) OVER (ORDER BY Reputation) / SUM(COUNT(*)) OVER()) AS CumPct
FROM Users
WHERE Reputation >= 200
GROUP BY Reputation) a
group by cumpct
having cumpct < 100
order by cumpct desc;

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